Re: can this be solved in Mathematica?
From The Last Danish Pastry <cli...@gmail.com>
· alt.ascii-art
· 17 Aug 2004 09:57 · View full thread
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That is very lovely. [cross-posted to alt.ascii-art] -- Clive Tooth http://www.clivetooth.dk "Anonym2004" <ano...@bamboo.com> wrote in message news:UPgUc.7041$Rt3...@newssvr29.news.prodigy.com... > in Mathematica 5.0: > Can the following equation: > > Out[3]= > \!\({P\_1 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_1\)\ C\_4 + B\_4\ \ > T\_1\)\/\((\(-b\) + V\_1)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ T\_1\)\ > \ > C\_3 + B\_3\ T\_1\)\/\((\(-b\) + V\_1)\)\^4 + \(A\_2 + \ > \[ExponentialE]\^\(\(-K\)\ T\_1\)\ C\_2 + B\_2\ T\_1\)\/\((\(-b\) + \ > V\_1)\)\^3 + \(A\_1 + \[ExponentialE]\^\(\(-K\)\ T\_1\)\ C\_1 + B\_1\ \ > T\_1\)\/\((\(-b\) + V\_1)\)\^2 + \(X\ T\_1\)\/\(\(-b\) + V\_1\), > P\_2 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_2\)\ C\_4 + B\_4\ T\_2\)\/\ > \((\(-b\) + V\_2)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ T\_2\)\ C\_3 + > B\ > \_3\ T\_2\)\/\((\(-b\) + V\_2)\)\^4 + \(A\_2 + \[ExponentialE]\^\(\(-K\)\ \ > T\_2\)\ C\_2 + B\_2\ T\_2\)\/\((\(-b\) + V\_2)\)\^3 + \(A\_1 + \ > \[ExponentialE]\^\(\(-K\)\ T\_2\)\ C\_1 + B\_1\ T\_2\)\/\((\(-b\) + \ > V\_2)\)\^2 + \(X\ T\_2\)\/\(\(-b\) + V\_2\), > P\_3 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_3\)\ C\_4 + B\_4\ T\_3\)\/\ > \((\(-b\) + V\_3)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ T\_3\)\ C\_3 + > B\ > \_3\ T\_3\)\/\((\(-b\) + V\_3)\)\^4 + \(A\_2 + \[ExponentialE]\^\(\(-K\)\ \ > T\_3\)\ C\_2 + B\_2\ T\_3\)\/\((\(-b\) + V\_3)\)\^3 + \(A\_1 + \ > \[ExponentialE]\^\(\(-K\)\ T\_3\)\ C\_1 + B\_1\ T\_3\)\/\((\(-b\) + \ > V\_3)\)\^2 + \(X\ T\_3\)\/\(\(-b\) + V\_3\), > P\_4 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_4\)\ C\_4 + B\_4\ T\_4\)\/\ > \((\(-b\) + V\_4)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ T\_4\)\ C\_3 + > B\ > \_3\ T\_4\)\/\((\(-b\) + V\_4)\)\^4 + \(A\_2 + \[ExponentialE]\^\(\(-K\)\ \ > T\_4\)\ C\_2 + B\_2\ T\_4\)\/\((\(-b\) + V\_4)\)\^3 + \(A\_1 + \ > \[ExponentialE]\^\(\(-K\)\ T\_4\)\ C\_1 + B\_1\ T\_4\)\/\((\(-b\) + \ > V\_4)\)\^2 + \(X\ T\_4\)\/\(\(-b\) + V\_4\), > P\_5 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_5\)\ C\_4 + B\_4\ T\_5\)\/\ > \((\(-b\) + V\_5)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ T\_5\)\ C\_3 + > B\ > \_3\ T\_5\)\/\((\(-b\) + V\_5)\)\^4 + \(A\_2 + \[ExponentialE]\^\(\(-K\)\ \ > T\_5\)\ C\_2 + B\_2\ T\_5\)\/\((\(-b\) + V\_5)\)\^3 + \(A\_1 + \ > \[ExponentialE]\^\(\(-K\)\ T\_5\)\ C\_1 + B\_1\ T\_5\)\/\((\(-b\) + \ > V\_5)\)\^2 + \(X\ T\_5\)\/\(\(-b\) + V\_5\), > P\_6 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_6\)\ C\_4 + B\_4\ T\_6\)\/\ > \((\(-b\) + V\_6)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ T\_6\)\ C\_3 + > B\ > \_3\ T\_6\)\/\((\(-b\) + V\_6)\)\^4 + \(A\_2 + \[ExponentialE]\^\(\(-K\)\ \ > T\_6\)\ C\_2 + B\_2\ T\_6\)\/\((\(-b\) + V\_6)\)\^3 + \(A\_1 + \ > \[ExponentialE]\^\(\(-K\)\ T\_6\)\ C\_1 + B\_1\ T\_6\)\/\((\(-b\) + \ > V\_6)\)\^2 + \(X\ T\_6\)\/\(\(-b\) + V\_6\), > P\_7 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_7\)\ C\_4 + B\_4\ T\_7\)\/\ > \((\(-b\) + V\_7)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ T\_7\)\ C\_3 + > B\ > \_3\ T\_7\)\/\((\(-b\) + V\_7)\)\^4 + \(A\_2 + \[ExponentialE]\^\(\(-K\)\ \ > T\_7\)\ C\_2 + B\_2\ T\_7\)\/\((\(-b\) + V\_7)\)\^3 + \(A\_1 + \ > \[ExponentialE]\^\(\(-K\)\ T\_7\)\ C\_1 + B\_1\ T\_7\)\/\((\(-b\) + \ > V\_7)\)\^2 + \(X\ T\_7\)\/\(\(-b\) + V\_7\), > P\_8 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_8\)\ C\_4 + B\_4\ T\_8\)\/\ > \((\(-b\) + V\_8)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ T\_8\)\ C\_3 + > B\ > \_3\ T\_8\)\/\((\(-b\) + V\_8)\)\^4 + \(A\_2 + \[ExponentialE]\^\(\(-K\)\ \ > T\_8\)\ C\_2 + B\_2\ T\_8\)\/\((\(-b\) + V\_8)\)\^3 + \(A\_1 + \ > \[ExponentialE]\^\(\(-K\)\ T\_8\)\ C\_1 + B\_1\ T\_8\)\/\((\(-b\) + \ > V\_8)\)\^2 + \(X\ T\_8\)\/\(\(-b\) + V\_8\), > P\_9 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_9\)\ C\_4 + B\_4\ T\_9\)\/\ > \((\(-b\) + V\_9)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ T\_9\)\ C\_3 + > B\ > \_3\ T\_9\)\/\((\(-b\) + V\_9)\)\^4 + \(A\_2 + \[ExponentialE]\^\(\(-K\)\ \ > T\_9\)\ C\_2 + B\_2\ T\_9\)\/\((\(-b\) + V\_9)\)\^3 + \(A\_1 + \ > \[ExponentialE]\^\(\(-K\)\ T\_9\)\ C\_1 + B\_1\ T\_9\)\/\((\(-b\) + \ > V\_9)\)\^2 + \(X\ T\_9\)\/\(\(-b\) + V\_9\), > P\_10 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_10\)\ C\_4 + B\_4\ \ > T\_10\)\/\((\(-b\) + V\_10)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ \ > T\_10\)\ C\_3 + B\_3\ T\_10\)\/\((\(-b\) + V\_10)\)\^4 + \(A\_2 + \ > \[ExponentialE]\^\(\(-K\)\ T\_10\)\ C\_2 + B\_2\ T\_10\)\/\((\(-b\) + \ > V\_10)\)\^3 + \(A\_1 + \[ExponentialE]\^\(\(-K\)\ T\_10\)\ C\_1 + B\_1\ > T\_10\ > \)\/\((\(-b\) + V\_10)\)\^2 + \(X\ T\_10\)\/\(\(-b\) + V\_10\), > P\_11 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_11\)\ C\_4 + B\_4\ \ > T\_11\)\/\((\(-b\) + V\_11)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ \ > T\_11\)\ C\_3 + B\_3\ T\_11\)\/\((\(-b\) + V\_11)\)\^4 + \(A\_2 + \ > \[ExponentialE]\^\(\(-K\)\ T\_11\)\ C\_2 + B\_2\ T\_11\)\/\((\(-b\) + \ > V\_11)\)\^3 + \(A\_1 + \[ExponentialE]\^\(\(-K\)\ T\_11\)\ C\_1 + B\_1\ > T\_11\ > \)\/\((\(-b\) + V\_11)\)\^2 + \(X\ T\_11\)\/\(\(-b\) + V\_11\), > P\_12 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_12\)\ C\_4 + B\_4\ \ > T\_12\)\/\((\(-b\) + V\_12)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ \ > T\_12\)\ C\_3 + B\_3\ T\_12\)\/\((\(-b\) + V\_12)\)\^4 + \(A\_2 + \ > \[ExponentialE]\^\(\(-K\)\ T\_12\)\ C\_2 + B\_2\ T\_12\)\/\((\(-b\) + \ > V\_12)\)\^3 + \(A\_1 + \[ExponentialE]\^\(\(-K\)\ T\_12\)\ C\_1 + B\_1\ > T\_12\ > \)\/\((\(-b\) + V\_12)\)\^2 + \(X\ T\_12\)\/\(\(-b\) + V\_12\), > P\_13 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_13\)\ C\_4 + B\_4\ \ > T\_13\)\/\((\(-b\) + V\_13)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ \ > T\_13\)\ C\_3 + B\_3\ T\_13\)\/\((\(-b\) + V\_13)\)\^4 + \(A\_2 + \ > \[ExponentialE]\^\(\(-K\)\ T\_13\)\ C\_2 + B\_2\ T\_13\)\/\((\(-b\) + \ > V\_13)\)\^3 + \(A\_1 + \[ExponentialE]\^\(\(-K\)\ T\_13\)\ C\_1 + B\_1\ > T\_13\ > \)\/\((\(-b\) + V\_13)\)\^2 + \(X\ T\_13\)\/\(\(-b\) + V\_13\), > P\_14 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_14\)\ C\_4 + B\_4\ \ > T\_14\)\/\((\(-b\) + V\_14)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ \ > T\_14\)\ C\_3 + B\_3\ T\_14\)\/\((\(-b\) + V\_14)\)\^4 + \(A\_2 + \ > \[ExponentialE]\^\(\(-K\)\ T\_14\)\ C\_2 + B\_2\ T\_14\)\/\((\(-b\) + \ > V\_14)\)\^3 + \(A\_1 + \[ExponentialE]\^\(\(-K\)\ T\_14\)\ C\_1 + B\_1\ > T\_14\ > \)\/\((\(-b\) + V\_14)\)\^2 + \(X\ T\_14\)\/\(\(-b\) + V\_14\), > P\_15 == \(A\_4 + \[ExponentialE]\^\(\(-K\)\ T\_15\)\ C\_4 + B\_4\ \ > T\_15\)\/\((\(-b\) + V\_15)\)\^5 + \(A\_3 + \[ExponentialE]\^\(\(-K\)\ \ > T\_15\)\ C\_3 + B\_3\ T\_15\)\/\((\(-b\) + V\_15)\)\^4 + \(A\_2 + \ > \[ExponentialE]\^\(\(-K\)\ T\_15\)\ C\_2 + B\_2\ T\_15\)\/\((\(-b\) + \ > V\_15)\)\^3 + \(A\_1 + \[ExponentialE]\^\(\(-K\)\ T\_15\)\ C\_1 + B\_1\ > T\_15\ > \)\/\((\(-b\) + V\_15)\)\^2 + \(X\ T\_15\)\/\(\(-b\) + V\_15\)}\) > > be solved for the following unknowns: > > In[4]:= > \!\({X, b, K, A\_1, A\_2, A\_3, A\_4, B\_1, B\_2, B\_3, B\_4, C\_1, C\_2, > C\_3, C\_4}\) > > > >
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X-Google-Thread: 109d8a,ec74c7ef1b62fdcf X-Google-Thread: f996b,664d02158adcf2d0,start X-Google-Attributes: gid109d8a,gidf996b,public X-Google-Language: ENGLISH,ASCII-7-bit Path: g2news1.google.com!news2.google.com!fu-berlin.de!uni-berlin.de!not-for-mail From: "The Last Danish Pastry" <cli...@gmail.com> Newsgroups: sci.math,alt.ascii-art Subject: Re: can this be solved in Mathematica? Date: Tue, 17 Aug 2004 10:57:24 +0100 Organization: Denna sida �r under uppdatering p� grund av SDFs flytt. Lines: 148 Message-ID: <2oe...@uni-berlin.de> References: <UPgUc.7041$Rt3...@newssvr29.news.prodigy.com> X-Trace: news.uni-berlin.de 7inRQ2r0q0y0E4G67OBMhQXHjvcvUGKeOECNGCdaKJReBZAr4= X-Priority: 3 X-MSMail-Priority: Normal X-Newsreader: Microsoft Outlook Express 6.00.2800.1437 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1441 Xref: g2news1.google.com sci.math:28163 alt.ascii-art:1099
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